The function of printing an expression's type

Andrey Karpov
Articles: 359

I very often meet debates in forums on what type this or that expression will have. So I decided to make a little note in the blog to refer to an example of code printing the type of an expression and information about it:

#include <iostream>
using namespace std;
template <typename T>
void PrintTypeInfo(char const* description, T)
  const type_info &info = typeid(T);
  cerr << "\"" << description << "\":"
       << " type = " <<
       << "; sizeof = " << sizeof (T)
       << "; alignof = " << __alignof (T)
       << endl;
int _tmain(int, _TCHAR *[])
  char c1 = 0, c2 = 0;
  PrintTypeInfo("char + char", c1 + c2);

The result:

"char + char": type = int; sizeof = 4; alignof = 4

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Andrey Karpov
Articles: 359

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