V590. Consider inspecting this expression. The expression is excessive or contains a misprint.


The analyzer detected a potential error: there is an excessive comparison in code. Let me explain this by a simple example:

if (Aa[42] == 10 && Aa[42] != 3)

The condition will hold if 'Aa == 10'. The second part of the expression is meaningless. On studying the code, you may come to one of the two conclusions:

1) The expression can be simplified. This is the fixed code:

if (Aa[42] == 10)

2) The expression has an error. This is the fixed code:

if (Aa[42] == 10 && Aa[43] != 3)

Let's study the example from practice. We have no error here, but the expression is excessive, which might make the code less readable:

while (*pBuff == ' ' && *pBuff != '\0')
  pBuff++;

The " *pBuff != '\0' " check is meaningless. This is the shortened code:

while (*pBuff == ' ')
  pBuff++;


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