V622. Consider inspecting the 'switch' statement. It's possible that the first 'case' operator is missing.

The analyzer has detected a potential error: the first operator in the 'switch' operator's block is not the 'case' operator. It causes the code fragment never to get control. Consider this example:

char B = '0';
int I;
...
switch(I)
{
  B = '1';
  break;
case 2:
  B = '2';
  break;
default:
  B = '3';
  break;
}

Assignment "B = '1';" will never be performed. This is the correct code:

switch(I)
{
case 1:
  B = '1';
  break;
case 2:
  B = '2';
  break;
default:
  B = '3';
  break;
}

According to Common Weakness Enumeration, potential errors found by using this diagnostic are classified as CWE-478.

You can look at examples of errors detected by the V622 diagnostic.


Bugs Found

Checked Projects
409
Collected Errors
14 072
This website uses cookies and other technology to provide you a more personalized experience. By continuing the view of our web-pages you accept the terms of using these files. If you don't want your personal data to be processed, please, leave this site. Learn More →
Accept