The analyzer has detected a potential error: comma ',' is written by accident instead of semicolon ';'. This misprint can lead to an incorrect logic of program execution. Consider an example:
int a; int b; ... if (a == 2) a++, b = a;
This code will result in executing the "b = a;" expression only when the 'if' operator's condition holds. This is most likely a misprint and ',' should be replaced with ';'. This is the correct code:
if (a == 2) a++; b = a;
The analyzer won't generate the message if formatting of a code fragment demonstrates deliberate use of the ',' operator. Here is a code sample:
if (a == 2) a++, b = a; if (a == 2) a++, b = a;
According to Common Weakness Enumeration, potential errors found by using this diagnostic are classified as CWE-483.
You can look at examples of errors detected by the V626 diagnostic.