V633. Consider inspecting the expression. Probably the '!=' should be used here.


The analyzer has detected a potential error. The '!=' or '==!' operator should be probably used instead of the '=!' operator. Such errors most often occur through misprints.

Consider an example of incorrect code:

int A, B;
...
if (A =! B)
{
  ...
}

It's most probably that this code should check that the 'A' variable is not equal to 'B'. If so, the correct code should look like follows:

if (A != B)
{
  ...
}

The analyzer accounts for formatting in the expression. That's why if it is exactly assignment you need to perform - not comparison - you should specify it through parentheses or blanks. The following code samples are considered correct:

if (A = !B)
  ...
if (A=(!B))
  ...

According to Common Weakness Enumeration, potential errors found by using this diagnostic are classified as CWE-480.


Bugs Found

Checked Projects
336
Collected Errors
12 743