The analyzer has detected a potential error when a forward slash is used.
It's easy to make a mistake mixing up the forward slash and backward slash characters.
if (x == '/n')
The programmer intended to compare the variable 'x' to the code 0xA (line feed) but made a mistake and wrote a forward slash. It results in the variable being compared to the value 0x2F6E.
This is the fixed code:
if (x == '\n')
Such a mistake is usually made when working with the following escape sequences: